`for x in itertools.product( A, repeat = 3 )`

Now, what if A has a special element X and you want only the ordered triples that include at least one X. What's the best way of doing so? (Assuming we want to pick only among the implementations which don't generate all triples and then filter.)

I was thinking of

A = complete set
X = mandatory element
Aprime = A - X
for i in xrange( 0, 3 ):
allowed = [ Aprime ] * i + [ [ X ] ] + [ A ] * ( 3 - i - 1 )
for x in itertools.product( *allowed ):
yield x

but this seems a bit indirect (of course, I'm allowing for the general case here.) The idea is to iterate over (X, any, any), then (not X, X, any) then (not X, not X, X) which should cover all possibilities exactly once.

Other alternatives?

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